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Solve 3x āˆ’ 11 = āˆ’32

The solution of 3x āˆ’ 11 = āˆ’32 is x = -7.

The lines y = 3x āˆ’ 11 and y = -32 meet at x = -7-12-10-8-6-4-2-50-45-40-35-30-25-20-15x = -7y = 3x āˆ’ 11y = -32
The lines y = 3x āˆ’ 11 and y = -32 meet at x = -7. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    3xāˆ’11=āˆ’323x - 11 = -32
  2. 2

    Add 11 to both sides:

    3xāˆ’11+11=āˆ’32+11 ⇒ 3x=āˆ’213x - 11 + 11 = -32 + 11 \ \Rightarrow\ 3x = -21
  3. 3

    Divide both sides by 3:

    3x3=āˆ’213 ⇒ x=āˆ’7\frac{3x}{3} = \frac{-21}{3} \ \Rightarrow\ x = -7
  4. 4

    Check: put x = -7 back into the equation.

    3ā‹…(āˆ’7)āˆ’11=āˆ’21āˆ’11=āˆ’32āœ“3\cdot(-7) - 11 = -21 - 11 = -32 \checkmark
LaTeX source of the formulas on this page
\[ 3x - 11 = -32\ \Rightarrow\ x = -7 \]
\[ 3x - 11 = -32 \]
\[ 3x - 11 + 11 = -32 + 11 \ \Rightarrow\ 3x = -21 \]
\[ \frac{3x}{3} = \frac{-21}{3} \ \Rightarrow\ x = -7 \]
\[ 3\cdot(-7) - 11 = -21 - 11 = -32 \checkmark \]

Trying values of x in 3x āˆ’ 11 = āˆ’32

x3x āˆ’ 11Equals -32?
-9-38no
-8-35no
-7-32yes
-6-29no
-5-26no

Questions

What is x in 3x āˆ’ 11 = āˆ’32?

The solution of 3x āˆ’ 11 = āˆ’32 is x = -7.

How do you solve 3x āˆ’ 11 = āˆ’32?

Add 11 to both sides to get 3x = -21, then divide both sides by 3 to get x = -7.

How do I check the answer?

Replace x by -7: 3(-7) āˆ’ 11 = -32, which is -32.

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    Solve 3x āˆ’ 11 = āˆ’32: x = -7 (steps and check) | WordGPT