Solve 3x ā 11 = 40
The solution of 3x ā 11 = 40 is x = 17.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.
- 2
Add 11 to both sides:
- 3
Divide both sides by 3:
- 4
Check: put x = 17 back into the equation.
LaTeX source of the formulas on this page
\[ 3x - 11 = 40\ \Rightarrow\ x = 17 \]
\[ 3x - 11 = 40 \]
\[ 3x - 11 + 11 = 40 + 11 \ \Rightarrow\ 3x = 51 \]
\[ \frac{3x}{3} = \frac{51}{3} \ \Rightarrow\ x = 17 \]
\[ 3\cdot17 - 11 = 51 - 11 = 40 \checkmark \]Trying values of x in 3x ā 11 = 40
| x | 3x ā 11 | Equals 40? |
|---|---|---|
| 15 | 34 | no |
| 16 | 37 | no |
| 17 | 40 | yes |
| 18 | 43 | no |
| 19 | 46 | no |
Questions
What is x in 3x ā 11 = 40?
The solution of 3x ā 11 = 40 is x = 17.
How do you solve 3x ā 11 = 40?
Add 11 to both sides to get 3x = 51, then divide both sides by 3 to get x = 17.
How do I check the answer?
Replace x by 17: 3(17) ā 11 = 40, which is 40.