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Solve 3x āˆ’ 10 = āˆ’40

The solution of 3x āˆ’ 10 = āˆ’40 is x = -10.

The lines y = 3x āˆ’ 10 and y = -40 meet at x = -10-16-14-12-10-8-6-4-60-55-50-45-40-35-30-25-20x = -10y = 3x āˆ’ 10y = -40
The lines y = 3x āˆ’ 10 and y = -40 meet at x = -10. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    3xāˆ’10=āˆ’403x - 10 = -40
  2. 2

    Add 10 to both sides:

    3xāˆ’10+10=āˆ’40+10 ⇒ 3x=āˆ’303x - 10 + 10 = -40 + 10 \ \Rightarrow\ 3x = -30
  3. 3

    Divide both sides by 3:

    3x3=āˆ’303 ⇒ x=āˆ’10\frac{3x}{3} = \frac{-30}{3} \ \Rightarrow\ x = -10
  4. 4

    Check: put x = -10 back into the equation.

    3ā‹…(āˆ’10)āˆ’10=āˆ’30āˆ’10=āˆ’40āœ“3\cdot(-10) - 10 = -30 - 10 = -40 \checkmark
LaTeX source of the formulas on this page
\[ 3x - 10 = -40\ \Rightarrow\ x = -10 \]
\[ 3x - 10 = -40 \]
\[ 3x - 10 + 10 = -40 + 10 \ \Rightarrow\ 3x = -30 \]
\[ \frac{3x}{3} = \frac{-30}{3} \ \Rightarrow\ x = -10 \]
\[ 3\cdot(-10) - 10 = -30 - 10 = -40 \checkmark \]

Trying values of x in 3x āˆ’ 10 = āˆ’40

x3x āˆ’ 10Equals -40?
-12-46no
-11-43no
-10-40yes
-9-37no
-8-34no

Questions

What is x in 3x āˆ’ 10 = āˆ’40?

The solution of 3x āˆ’ 10 = āˆ’40 is x = -10.

How do you solve 3x āˆ’ 10 = āˆ’40?

Add 10 to both sides to get 3x = -30, then divide both sides by 3 to get x = -10.

How do I check the answer?

Replace x by -10: 3(-10) āˆ’ 10 = -40, which is -40.

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    Solve 3x āˆ’ 10 = āˆ’40: x = -10 (steps and check) | WordGPT