Solve 3x ā 10 = 47
The solution of 3x ā 10 = 47 is x = 19.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.
- 2
Add 10 to both sides:
- 3
Divide both sides by 3:
- 4
Check: put x = 19 back into the equation.
LaTeX source of the formulas on this page
\[ 3x - 10 = 47\ \Rightarrow\ x = 19 \]
\[ 3x - 10 = 47 \]
\[ 3x - 10 + 10 = 47 + 10 \ \Rightarrow\ 3x = 57 \]
\[ \frac{3x}{3} = \frac{57}{3} \ \Rightarrow\ x = 19 \]
\[ 3\cdot19 - 10 = 57 - 10 = 47 \checkmark \]Trying values of x in 3x ā 10 = 47
| x | 3x ā 10 | Equals 47? |
|---|---|---|
| 17 | 41 | no |
| 18 | 44 | no |
| 19 | 47 | yes |
| 20 | 50 | no |
| 21 | 53 | no |
Questions
What is x in 3x ā 10 = 47?
The solution of 3x ā 10 = 47 is x = 19.
How do you solve 3x ā 10 = 47?
Add 10 to both sides to get 3x = 57, then divide both sides by 3 to get x = 19.
How do I check the answer?
Replace x by 19: 3(19) ā 10 = 47, which is 47.