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Solve 3x āˆ’ 10 = 20

The solution of 3x āˆ’ 10 = 20 is x = 10.

The lines y = 3x āˆ’ 10 and y = 20 meet at x = 1046810121416510152025303540x = 10y = 3x āˆ’ 10y = 20
The lines y = 3x āˆ’ 10 and y = 20 meet at x = 10. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    3xāˆ’10=203x - 10 = 20
  2. 2

    Add 10 to both sides:

    3xāˆ’10+10=20+10 ⇒ 3x=303x - 10 + 10 = 20 + 10 \ \Rightarrow\ 3x = 30
  3. 3

    Divide both sides by 3:

    3x3=303 ⇒ x=10\frac{3x}{3} = \frac{30}{3} \ \Rightarrow\ x = 10
  4. 4

    Check: put x = 10 back into the equation.

    3ā‹…10āˆ’10=30āˆ’10=20āœ“3\cdot10 - 10 = 30 - 10 = 20 \checkmark
LaTeX source of the formulas on this page
\[ 3x - 10 = 20\ \Rightarrow\ x = 10 \]
\[ 3x - 10 = 20 \]
\[ 3x - 10 + 10 = 20 + 10 \ \Rightarrow\ 3x = 30 \]
\[ \frac{3x}{3} = \frac{30}{3} \ \Rightarrow\ x = 10 \]
\[ 3\cdot10 - 10 = 30 - 10 = 20 \checkmark \]

Trying values of x in 3x āˆ’ 10 = 20

x3x āˆ’ 10Equals 20?
814no
917no
1020yes
1123no
1226no

Questions

What is x in 3x āˆ’ 10 = 20?

The solution of 3x āˆ’ 10 = 20 is x = 10.

How do you solve 3x āˆ’ 10 = 20?

Add 10 to both sides to get 3x = 30, then divide both sides by 3 to get x = 10.

How do I check the answer?

Replace x by 10: 3(10) āˆ’ 10 = 20, which is 20.

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