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Solve 3x āˆ’ 1 = 47

The solution of 3x āˆ’ 1 = 47 is x = 16.

The lines y = 3x āˆ’ 1 and y = 47 meet at x = 16101214161820223035404550556065x = 16y = 3x āˆ’ 1y = 47
The lines y = 3x āˆ’ 1 and y = 47 meet at x = 16. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    3xāˆ’1=473x - 1 = 47
  2. 2

    Add 1 to both sides:

    3xāˆ’1+1=47+1 ⇒ 3x=483x - 1 + 1 = 47 + 1 \ \Rightarrow\ 3x = 48
  3. 3

    Divide both sides by 3:

    3x3=483 ⇒ x=16\frac{3x}{3} = \frac{48}{3} \ \Rightarrow\ x = 16
  4. 4

    Check: put x = 16 back into the equation.

    3ā‹…16āˆ’1=48āˆ’1=47āœ“3\cdot16 - 1 = 48 - 1 = 47 \checkmark
LaTeX source of the formulas on this page
\[ 3x - 1 = 47\ \Rightarrow\ x = 16 \]
\[ 3x - 1 = 47 \]
\[ 3x - 1 + 1 = 47 + 1 \ \Rightarrow\ 3x = 48 \]
\[ \frac{3x}{3} = \frac{48}{3} \ \Rightarrow\ x = 16 \]
\[ 3\cdot16 - 1 = 48 - 1 = 47 \checkmark \]

Trying values of x in 3x āˆ’ 1 = 47

x3x āˆ’ 1Equals 47?
1441no
1544no
1647yes
1750no
1853no

Questions

What is x in 3x āˆ’ 1 = 47?

The solution of 3x āˆ’ 1 = 47 is x = 16.

How do you solve 3x āˆ’ 1 = 47?

Add 1 to both sides to get 3x = 48, then divide both sides by 3 to get x = 16.

How do I check the answer?

Replace x by 16: 3(16) āˆ’ 1 = 47, which is 47.

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    Solve 3x āˆ’ 1 = 47: x = 16 (steps and check) | WordGPT