Solve 3x ā 1 = 32
The solution of 3x ā 1 = 32 is x = 11.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.
- 2
Add 1 to both sides:
- 3
Divide both sides by 3:
- 4
Check: put x = 11 back into the equation.
LaTeX source of the formulas on this page
\[ 3x - 1 = 32\ \Rightarrow\ x = 11 \]
\[ 3x - 1 = 32 \]
\[ 3x - 1 + 1 = 32 + 1 \ \Rightarrow\ 3x = 33 \]
\[ \frac{3x}{3} = \frac{33}{3} \ \Rightarrow\ x = 11 \]
\[ 3\cdot11 - 1 = 33 - 1 = 32 \checkmark \]Trying values of x in 3x ā 1 = 32
| x | 3x ā 1 | Equals 32? |
|---|---|---|
| 9 | 26 | no |
| 10 | 29 | no |
| 11 | 32 | yes |
| 12 | 35 | no |
| 13 | 38 | no |
Questions
What is x in 3x ā 1 = 32?
The solution of 3x ā 1 = 32 is x = 11.
How do you solve 3x ā 1 = 32?
Add 1 to both sides to get 3x = 33, then divide both sides by 3 to get x = 11.
How do I check the answer?
Replace x by 11: 3(11) ā 1 = 32, which is 32.