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Solve 3x āˆ’ 1 = 32

The solution of 3x āˆ’ 1 = 32 is x = 11.

The lines y = 3x āˆ’ 1 and y = 32 meet at x = 1168101214161520253035404550x = 11y = 3x āˆ’ 1y = 32
The lines y = 3x āˆ’ 1 and y = 32 meet at x = 11. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    3xāˆ’1=323x - 1 = 32
  2. 2

    Add 1 to both sides:

    3xāˆ’1+1=32+1 ⇒ 3x=333x - 1 + 1 = 32 + 1 \ \Rightarrow\ 3x = 33
  3. 3

    Divide both sides by 3:

    3x3=333 ⇒ x=11\frac{3x}{3} = \frac{33}{3} \ \Rightarrow\ x = 11
  4. 4

    Check: put x = 11 back into the equation.

    3ā‹…11āˆ’1=33āˆ’1=32āœ“3\cdot11 - 1 = 33 - 1 = 32 \checkmark
LaTeX source of the formulas on this page
\[ 3x - 1 = 32\ \Rightarrow\ x = 11 \]
\[ 3x - 1 = 32 \]
\[ 3x - 1 + 1 = 32 + 1 \ \Rightarrow\ 3x = 33 \]
\[ \frac{3x}{3} = \frac{33}{3} \ \Rightarrow\ x = 11 \]
\[ 3\cdot11 - 1 = 33 - 1 = 32 \checkmark \]

Trying values of x in 3x āˆ’ 1 = 32

x3x āˆ’ 1Equals 32?
926no
1029no
1132yes
1235no
1338no

Questions

What is x in 3x āˆ’ 1 = 32?

The solution of 3x āˆ’ 1 = 32 is x = 11.

How do you solve 3x āˆ’ 1 = 32?

Add 1 to both sides to get 3x = 33, then divide both sides by 3 to get x = 11.

How do I check the answer?

Replace x by 11: 3(11) āˆ’ 1 = 32, which is 32.

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    Solve 3x āˆ’ 1 = 32: x = 11 (steps and check) | WordGPT