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Solve 2x + 8 = āˆ’2

The solution of 2x + 8 = āˆ’2 is x = -5.

The lines y = 2x + 8 and y = -2 meet at x = -5-10-8-6-4-2-15-10-5510x = -5y = 2x + 8y = -2
The lines y = 2x + 8 and y = -2 meet at x = -5. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    2x+8=āˆ’22x + 8 = -2
  2. 2

    Subtract 8 from both sides:

    2x+8āˆ’8=āˆ’2āˆ’8 ⇒ 2x=āˆ’102x + 8 - 8 = -2 - 8 \ \Rightarrow\ 2x = -10
  3. 3

    Divide both sides by 2:

    2x2=āˆ’102 ⇒ x=āˆ’5\frac{2x}{2} = \frac{-10}{2} \ \Rightarrow\ x = -5
  4. 4

    Check: put x = -5 back into the equation.

    2ā‹…(āˆ’5)+8=āˆ’10+8=āˆ’2āœ“2\cdot(-5) + 8 = -10 + 8 = -2 \checkmark
LaTeX source of the formulas on this page
\[ 2x + 8 = -2\ \Rightarrow\ x = -5 \]
\[ 2x + 8 = -2 \]
\[ 2x + 8 - 8 = -2 - 8 \ \Rightarrow\ 2x = -10 \]
\[ \frac{2x}{2} = \frac{-10}{2} \ \Rightarrow\ x = -5 \]
\[ 2\cdot(-5) + 8 = -10 + 8 = -2 \checkmark \]

Trying values of x in 2x + 8 = āˆ’2

x2x + 8Equals -2?
-7-6no
-6-4no
-5-2yes
-40no
-32no

Questions

What is x in 2x + 8 = āˆ’2?

The solution of 2x + 8 = āˆ’2 is x = -5.

How do you solve 2x + 8 = āˆ’2?

Subtract 8 from both sides to get 2x = -10, then divide both sides by 2 to get x = -5.

How do I check the answer?

Replace x by -5: 2(-5) + 8 = -2, which is -2.

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    Solve 2x + 8 = āˆ’2: x = -5 (steps and check) | WordGPT