Solve 2x + 8 = ā2
The solution of 2x + 8 = ā2 is x = -5.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 8 from both sides:
- 3
Divide both sides by 2:
- 4
Check: put x = -5 back into the equation.
LaTeX source of the formulas on this page
\[ 2x + 8 = -2\ \Rightarrow\ x = -5 \]
\[ 2x + 8 = -2 \]
\[ 2x + 8 - 8 = -2 - 8 \ \Rightarrow\ 2x = -10 \]
\[ \frac{2x}{2} = \frac{-10}{2} \ \Rightarrow\ x = -5 \]
\[ 2\cdot(-5) + 8 = -10 + 8 = -2 \checkmark \]Trying values of x in 2x + 8 = ā2
| x | 2x + 8 | Equals -2? |
|---|---|---|
| -7 | -6 | no |
| -6 | -4 | no |
| -5 | -2 | yes |
| -4 | 0 | no |
| -3 | 2 | no |
Questions
What is x in 2x + 8 = ā2?
The solution of 2x + 8 = ā2 is x = -5.
How do you solve 2x + 8 = ā2?
Subtract 8 from both sides to get 2x = -10, then divide both sides by 2 to get x = -5.
How do I check the answer?
Replace x by -5: 2(-5) + 8 = -2, which is -2.