Solve 2x + 8 = ā12
The solution of 2x + 8 = ā12 is x = -10.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 8 from both sides:
- 3
Divide both sides by 2:
- 4
Check: put x = -10 back into the equation.
LaTeX source of the formulas on this page
\[ 2x + 8 = -12\ \Rightarrow\ x = -10 \]
\[ 2x + 8 = -12 \]
\[ 2x + 8 - 8 = -12 - 8 \ \Rightarrow\ 2x = -20 \]
\[ \frac{2x}{2} = \frac{-20}{2} \ \Rightarrow\ x = -10 \]
\[ 2\cdot(-10) + 8 = -20 + 8 = -12 \checkmark \]Trying values of x in 2x + 8 = ā12
| x | 2x + 8 | Equals -12? |
|---|---|---|
| -12 | -16 | no |
| -11 | -14 | no |
| -10 | -12 | yes |
| -9 | -10 | no |
| -8 | -8 | no |
Questions
What is x in 2x + 8 = ā12?
The solution of 2x + 8 = ā12 is x = -10.
How do you solve 2x + 8 = ā12?
Subtract 8 from both sides to get 2x = -20, then divide both sides by 2 to get x = -10.
How do I check the answer?
Replace x by -10: 2(-10) + 8 = -12, which is -12.