Solve 2x + 7 = 33
The solution of 2x + 7 = 33 is x = 13.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 7 from both sides:
- 3
Divide both sides by 2:
- 4
Check: put x = 13 back into the equation.
LaTeX source of the formulas on this page
\[ 2x + 7 = 33\ \Rightarrow\ x = 13 \]
\[ 2x + 7 = 33 \]
\[ 2x + 7 - 7 = 33 - 7 \ \Rightarrow\ 2x = 26 \]
\[ \frac{2x}{2} = \frac{26}{2} \ \Rightarrow\ x = 13 \]
\[ 2\cdot13 + 7 = 26 + 7 = 33 \checkmark \]Trying values of x in 2x + 7 = 33
| x | 2x + 7 | Equals 33? |
|---|---|---|
| 11 | 29 | no |
| 12 | 31 | no |
| 13 | 33 | yes |
| 14 | 35 | no |
| 15 | 37 | no |
Questions
What is x in 2x + 7 = 33?
The solution of 2x + 7 = 33 is x = 13.
How do you solve 2x + 7 = 33?
Subtract 7 from both sides to get 2x = 26, then divide both sides by 2 to get x = 13.
How do I check the answer?
Replace x by 13: 2(13) + 7 = 33, which is 33.