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Solve 2x + 5 = āˆ’1

The solution of 2x + 5 = āˆ’1 is x = -3.

The lines y = 2x + 5 and y = -1 meet at x = -3-8-6-4-22-15-10-5510x = -3y = 2x + 5y = -1
The lines y = 2x + 5 and y = -1 meet at x = -3. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    2x+5=āˆ’12x + 5 = -1
  2. 2

    Subtract 5 from both sides:

    2x+5āˆ’5=āˆ’1āˆ’5 ⇒ 2x=āˆ’62x + 5 - 5 = -1 - 5 \ \Rightarrow\ 2x = -6
  3. 3

    Divide both sides by 2:

    2x2=āˆ’62 ⇒ x=āˆ’3\frac{2x}{2} = \frac{-6}{2} \ \Rightarrow\ x = -3
  4. 4

    Check: put x = -3 back into the equation.

    2ā‹…(āˆ’3)+5=āˆ’6+5=āˆ’1āœ“2\cdot(-3) + 5 = -6 + 5 = -1 \checkmark
LaTeX source of the formulas on this page
\[ 2x + 5 = -1\ \Rightarrow\ x = -3 \]
\[ 2x + 5 = -1 \]
\[ 2x + 5 - 5 = -1 - 5 \ \Rightarrow\ 2x = -6 \]
\[ \frac{2x}{2} = \frac{-6}{2} \ \Rightarrow\ x = -3 \]
\[ 2\cdot(-3) + 5 = -6 + 5 = -1 \checkmark \]

Trying values of x in 2x + 5 = āˆ’1

x2x + 5Equals -1?
-5-5no
-4-3no
-3-1yes
-21no
-13no

Questions

What is x in 2x + 5 = āˆ’1?

The solution of 2x + 5 = āˆ’1 is x = -3.

How do you solve 2x + 5 = āˆ’1?

Subtract 5 from both sides to get 2x = -6, then divide both sides by 2 to get x = -3.

How do I check the answer?

Replace x by -3: 2(-3) + 5 = -1, which is -1.

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    Solve 2x + 5 = āˆ’1: x = -3 (steps and check) | WordGPT