Solve 2x + 5 = 7
The solution of 2x + 5 = 7 is x = 1.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 5 from both sides:
- 3
Divide both sides by 2:
- 4
Check: put x = 1 back into the equation.
LaTeX source of the formulas on this page
\[ 2x + 5 = 7\ \Rightarrow\ x = 1 \]
\[ 2x + 5 = 7 \]
\[ 2x + 5 - 5 = 7 - 5 \ \Rightarrow\ 2x = 2 \]
\[ \frac{2x}{2} = \frac{2}{2} \ \Rightarrow\ x = 1 \]
\[ 2\cdot1 + 5 = 2 + 5 = 7 \checkmark \]Trying values of x in 2x + 5 = 7
| x | 2x + 5 | Equals 7? |
|---|---|---|
| -1 | 3 | no |
| 0 | 5 | no |
| 1 | 7 | yes |
| 2 | 9 | no |
| 3 | 11 | no |
Questions
What is x in 2x + 5 = 7?
The solution of 2x + 5 = 7 is x = 1.
How do you solve 2x + 5 = 7?
Subtract 5 from both sides to get 2x = 2, then divide both sides by 2 to get x = 1.
How do I check the answer?
Replace x by 1: 2(1) + 5 = 7, which is 7.