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Solve 2x + 4 = āˆ’2

The solution of 2x + 4 = āˆ’2 is x = -3.

The lines y = 2x + 4 and y = -2 meet at x = -3-8-6-4-22-15-10-5510x = -3y = 2x + 4y = -2
The lines y = 2x + 4 and y = -2 meet at x = -3. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    2x+4=āˆ’22x + 4 = -2
  2. 2

    Subtract 4 from both sides:

    2x+4āˆ’4=āˆ’2āˆ’4 ⇒ 2x=āˆ’62x + 4 - 4 = -2 - 4 \ \Rightarrow\ 2x = -6
  3. 3

    Divide both sides by 2:

    2x2=āˆ’62 ⇒ x=āˆ’3\frac{2x}{2} = \frac{-6}{2} \ \Rightarrow\ x = -3
  4. 4

    Check: put x = -3 back into the equation.

    2ā‹…(āˆ’3)+4=āˆ’6+4=āˆ’2āœ“2\cdot(-3) + 4 = -6 + 4 = -2 \checkmark
LaTeX source of the formulas on this page
\[ 2x + 4 = -2\ \Rightarrow\ x = -3 \]
\[ 2x + 4 = -2 \]
\[ 2x + 4 - 4 = -2 - 4 \ \Rightarrow\ 2x = -6 \]
\[ \frac{2x}{2} = \frac{-6}{2} \ \Rightarrow\ x = -3 \]
\[ 2\cdot(-3) + 4 = -6 + 4 = -2 \checkmark \]

Trying values of x in 2x + 4 = āˆ’2

x2x + 4Equals -2?
-5-6no
-4-4no
-3-2yes
-20no
-12no

Questions

What is x in 2x + 4 = āˆ’2?

The solution of 2x + 4 = āˆ’2 is x = -3.

How do you solve 2x + 4 = āˆ’2?

Subtract 4 from both sides to get 2x = -6, then divide both sides by 2 to get x = -3.

How do I check the answer?

Replace x by -3: 2(-3) + 4 = -2, which is -2.

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    Solve 2x + 4 = āˆ’2: x = -3 (steps and check) | WordGPT