Solve 2x + 4 = 38
The solution of 2x + 4 = 38 is x = 17.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 4 from both sides:
- 3
Divide both sides by 2:
- 4
Check: put x = 17 back into the equation.
LaTeX source of the formulas on this page
\[ 2x + 4 = 38\ \Rightarrow\ x = 17 \]
\[ 2x + 4 = 38 \]
\[ 2x + 4 - 4 = 38 - 4 \ \Rightarrow\ 2x = 34 \]
\[ \frac{2x}{2} = \frac{34}{2} \ \Rightarrow\ x = 17 \]
\[ 2\cdot17 + 4 = 34 + 4 = 38 \checkmark \]Trying values of x in 2x + 4 = 38
| x | 2x + 4 | Equals 38? |
|---|---|---|
| 15 | 34 | no |
| 16 | 36 | no |
| 17 | 38 | yes |
| 18 | 40 | no |
| 19 | 42 | no |
Questions
What is x in 2x + 4 = 38?
The solution of 2x + 4 = 38 is x = 17.
How do you solve 2x + 4 = 38?
Subtract 4 from both sides to get 2x = 34, then divide both sides by 2 to get x = 17.
How do I check the answer?
Replace x by 17: 2(17) + 4 = 38, which is 38.