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Solve 2x + 3 = āˆ’1

The solution of 2x + 3 = āˆ’1 is x = -2.

The lines y = 2x + 3 and y = -1 meet at x = -2-8-6-4-224-15-10-5510x = -2y = 2x + 3y = -1
The lines y = 2x + 3 and y = -1 meet at x = -2. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    2x+3=āˆ’12x + 3 = -1
  2. 2

    Subtract 3 from both sides:

    2x+3āˆ’3=āˆ’1āˆ’3 ⇒ 2x=āˆ’42x + 3 - 3 = -1 - 3 \ \Rightarrow\ 2x = -4
  3. 3

    Divide both sides by 2:

    2x2=āˆ’42 ⇒ x=āˆ’2\frac{2x}{2} = \frac{-4}{2} \ \Rightarrow\ x = -2
  4. 4

    Check: put x = -2 back into the equation.

    2ā‹…(āˆ’2)+3=āˆ’4+3=āˆ’1āœ“2\cdot(-2) + 3 = -4 + 3 = -1 \checkmark
LaTeX source of the formulas on this page
\[ 2x + 3 = -1\ \Rightarrow\ x = -2 \]
\[ 2x + 3 = -1 \]
\[ 2x + 3 - 3 = -1 - 3 \ \Rightarrow\ 2x = -4 \]
\[ \frac{2x}{2} = \frac{-4}{2} \ \Rightarrow\ x = -2 \]
\[ 2\cdot(-2) + 3 = -4 + 3 = -1 \checkmark \]

Trying values of x in 2x + 3 = āˆ’1

x2x + 3Equals -1?
-4-5no
-3-3no
-2-1yes
-11no
03no

Questions

What is x in 2x + 3 = āˆ’1?

The solution of 2x + 3 = āˆ’1 is x = -2.

How do you solve 2x + 3 = āˆ’1?

Subtract 3 from both sides to get 2x = -4, then divide both sides by 2 to get x = -2.

How do I check the answer?

Replace x by -2: 2(-2) + 3 = -1, which is -1.

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    Solve 2x + 3 = āˆ’1: x = -2 (steps and check) | WordGPT