Solve 2x + 2 = 22
The solution of 2x + 2 = 22 is x = 10.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 2 from both sides:
- 3
Divide both sides by 2:
- 4
Check: put x = 10 back into the equation.
LaTeX source of the formulas on this page
\[ 2x + 2 = 22\ \Rightarrow\ x = 10 \]
\[ 2x + 2 = 22 \]
\[ 2x + 2 - 2 = 22 - 2 \ \Rightarrow\ 2x = 20 \]
\[ \frac{2x}{2} = \frac{20}{2} \ \Rightarrow\ x = 10 \]
\[ 2\cdot10 + 2 = 20 + 2 = 22 \checkmark \]Trying values of x in 2x + 2 = 22
| x | 2x + 2 | Equals 22? |
|---|---|---|
| 8 | 18 | no |
| 9 | 20 | no |
| 10 | 22 | yes |
| 11 | 24 | no |
| 12 | 26 | no |
Questions
What is x in 2x + 2 = 22?
The solution of 2x + 2 = 22 is x = 10.
How do you solve 2x + 2 = 22?
Subtract 2 from both sides to get 2x = 20, then divide both sides by 2 to get x = 10.
How do I check the answer?
Replace x by 10: 2(10) + 2 = 22, which is 22.