Solve 2x + 15 = 41

The solution of 2x + 15 = 41 is x = 13.

2x + 15 = 41\ \Rightarrow\ x = 13

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The lines y = 2x + 15 and y = 41 meet at x = 13. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
$2x + 15 = 41$
2
Subtract 15 from both sides:
$2x + 15 - 15 = 41 - 15 \ \Rightarrow\ 2x = 26$
3
Divide both sides by 2:
$\frac{2x}{2} = \frac{26}{2} \ \Rightarrow\ x = 13$
4
Check: put x = 13 back into the equation.
$2\cdot13 + 15 = 26 + 15 = 41 \checkmark$

LaTeX source of the formulas on this page

\[ 2x + 15 = 41\ \Rightarrow\ x = 13 \]
\[ 2x + 15 = 41 \]
\[ 2x + 15 - 15 = 41 - 15 \ \Rightarrow\ 2x = 26 \]
\[ \frac{2x}{2} = \frac{26}{2} \ \Rightarrow\ x = 13 \]
\[ 2\cdot13 + 15 = 26 + 15 = 41 \checkmark \]

Trying values of x in 2x + 15 = 41

x	2x + 15	Equals 41?
11	37	no
12	39	no
13	41	yes
14	43	no
15	45	no

Questions

What is x in 2x + 15 = 41?

The solution of 2x + 15 = 41 is x = 13.

How do you solve 2x + 15 = 41?

Subtract 15 from both sides to get 2x = 26, then divide both sides by 2 to get x = 13.

How do I check the answer?

Replace x by 13: 2(13) + 15 = 41, which is 41.

Solve 2x + 15 = 41

How to work it out

Trying values of x in 2x + 15 = 41

Questions

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