Solve 2x + 11 = ā3
The solution of 2x + 11 = ā3 is x = -7.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 11 from both sides:
- 3
Divide both sides by 2:
- 4
Check: put x = -7 back into the equation.
LaTeX source of the formulas on this page
\[ 2x + 11 = -3\ \Rightarrow\ x = -7 \]
\[ 2x + 11 = -3 \]
\[ 2x + 11 - 11 = -3 - 11 \ \Rightarrow\ 2x = -14 \]
\[ \frac{2x}{2} = \frac{-14}{2} \ \Rightarrow\ x = -7 \]
\[ 2\cdot(-7) + 11 = -14 + 11 = -3 \checkmark \]Trying values of x in 2x + 11 = ā3
| x | 2x + 11 | Equals -3? |
|---|---|---|
| -9 | -7 | no |
| -8 | -5 | no |
| -7 | -3 | yes |
| -6 | -1 | no |
| -5 | 1 | no |
Questions
What is x in 2x + 11 = ā3?
The solution of 2x + 11 = ā3 is x = -7.
How do you solve 2x + 11 = ā3?
Subtract 11 from both sides to get 2x = -14, then divide both sides by 2 to get x = -7.
How do I check the answer?
Replace x by -7: 2(-7) + 11 = -3, which is -3.