Solve 2x + 10 = ā10
The solution of 2x + 10 = ā10 is x = -10.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 10 from both sides:
- 3
Divide both sides by 2:
- 4
Check: put x = -10 back into the equation.
LaTeX source of the formulas on this page
\[ 2x + 10 = -10\ \Rightarrow\ x = -10 \]
\[ 2x + 10 = -10 \]
\[ 2x + 10 - 10 = -10 - 10 \ \Rightarrow\ 2x = -20 \]
\[ \frac{2x}{2} = \frac{-20}{2} \ \Rightarrow\ x = -10 \]
\[ 2\cdot(-10) + 10 = -20 + 10 = -10 \checkmark \]Trying values of x in 2x + 10 = ā10
| x | 2x + 10 | Equals -10? |
|---|---|---|
| -12 | -14 | no |
| -11 | -12 | no |
| -10 | -10 | yes |
| -9 | -8 | no |
| -8 | -6 | no |
Questions
What is x in 2x + 10 = ā10?
The solution of 2x + 10 = ā10 is x = -10.
How do you solve 2x + 10 = ā10?
Subtract 10 from both sides to get 2x = -20, then divide both sides by 2 to get x = -10.
How do I check the answer?
Replace x by -10: 2(-10) + 10 = -10, which is -10.