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Solve 2x āˆ’ 6 = āˆ’2

The solution of 2x āˆ’ 6 = āˆ’2 is x = 2.

The lines y = 2x āˆ’ 6 and y = -2 meet at x = 2-4-22468-15-10-5510x = 2y = 2x āˆ’ 6y = -2
The lines y = 2x āˆ’ 6 and y = -2 meet at x = 2. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    2xāˆ’6=āˆ’22x - 6 = -2
  2. 2

    Add 6 to both sides:

    2xāˆ’6+6=āˆ’2+6 ⇒ 2x=42x - 6 + 6 = -2 + 6 \ \Rightarrow\ 2x = 4
  3. 3

    Divide both sides by 2:

    2x2=42 ⇒ x=2\frac{2x}{2} = \frac{4}{2} \ \Rightarrow\ x = 2
  4. 4

    Check: put x = 2 back into the equation.

    2ā‹…2āˆ’6=4āˆ’6=āˆ’2āœ“2\cdot2 - 6 = 4 - 6 = -2 \checkmark
LaTeX source of the formulas on this page
\[ 2x - 6 = -2\ \Rightarrow\ x = 2 \]
\[ 2x - 6 = -2 \]
\[ 2x - 6 + 6 = -2 + 6 \ \Rightarrow\ 2x = 4 \]
\[ \frac{2x}{2} = \frac{4}{2} \ \Rightarrow\ x = 2 \]
\[ 2\cdot2 - 6 = 4 - 6 = -2 \checkmark \]

Trying values of x in 2x āˆ’ 6 = āˆ’2

x2x āˆ’ 6Equals -2?
0-6no
1-4no
2-2yes
30no
42no

Questions

What is x in 2x āˆ’ 6 = āˆ’2?

The solution of 2x āˆ’ 6 = āˆ’2 is x = 2.

How do you solve 2x āˆ’ 6 = āˆ’2?

Add 6 to both sides to get 2x = 4, then divide both sides by 2 to get x = 2.

How do I check the answer?

Replace x by 2: 2(2) āˆ’ 6 = -2, which is -2.

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