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Solve 2x āˆ’ 5 = āˆ’25

The solution of 2x āˆ’ 5 = āˆ’25 is x = -10.

The lines y = 2x āˆ’ 5 and y = -25 meet at x = -10-16-14-12-10-8-6-4-35-30-25-20-15x = -10y = 2x āˆ’ 5y = -25
The lines y = 2x āˆ’ 5 and y = -25 meet at x = -10. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    2xāˆ’5=āˆ’252x - 5 = -25
  2. 2

    Add 5 to both sides:

    2xāˆ’5+5=āˆ’25+5 ⇒ 2x=āˆ’202x - 5 + 5 = -25 + 5 \ \Rightarrow\ 2x = -20
  3. 3

    Divide both sides by 2:

    2x2=āˆ’202 ⇒ x=āˆ’10\frac{2x}{2} = \frac{-20}{2} \ \Rightarrow\ x = -10
  4. 4

    Check: put x = -10 back into the equation.

    2ā‹…(āˆ’10)āˆ’5=āˆ’20āˆ’5=āˆ’25āœ“2\cdot(-10) - 5 = -20 - 5 = -25 \checkmark
LaTeX source of the formulas on this page
\[ 2x - 5 = -25\ \Rightarrow\ x = -10 \]
\[ 2x - 5 = -25 \]
\[ 2x - 5 + 5 = -25 + 5 \ \Rightarrow\ 2x = -20 \]
\[ \frac{2x}{2} = \frac{-20}{2} \ \Rightarrow\ x = -10 \]
\[ 2\cdot(-10) - 5 = -20 - 5 = -25 \checkmark \]

Trying values of x in 2x āˆ’ 5 = āˆ’25

x2x āˆ’ 5Equals -25?
-12-29no
-11-27no
-10-25yes
-9-23no
-8-21no

Questions

What is x in 2x āˆ’ 5 = āˆ’25?

The solution of 2x āˆ’ 5 = āˆ’25 is x = -10.

How do you solve 2x āˆ’ 5 = āˆ’25?

Add 5 to both sides to get 2x = -20, then divide both sides by 2 to get x = -10.

How do I check the answer?

Replace x by -10: 2(-10) āˆ’ 5 = -25, which is -25.

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    Solve 2x āˆ’ 5 = āˆ’25: x = -10 (steps and check) | WordGPT