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Solve 2x āˆ’ 5 = āˆ’1

The solution of 2x āˆ’ 5 = āˆ’1 is x = 2.

The lines y = 2x āˆ’ 5 and y = -1 meet at x = 2-4-22468-15-10-5510x = 2y = 2x āˆ’ 5y = -1
The lines y = 2x āˆ’ 5 and y = -1 meet at x = 2. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    2xāˆ’5=āˆ’12x - 5 = -1
  2. 2

    Add 5 to both sides:

    2xāˆ’5+5=āˆ’1+5 ⇒ 2x=42x - 5 + 5 = -1 + 5 \ \Rightarrow\ 2x = 4
  3. 3

    Divide both sides by 2:

    2x2=42 ⇒ x=2\frac{2x}{2} = \frac{4}{2} \ \Rightarrow\ x = 2
  4. 4

    Check: put x = 2 back into the equation.

    2ā‹…2āˆ’5=4āˆ’5=āˆ’1āœ“2\cdot2 - 5 = 4 - 5 = -1 \checkmark
LaTeX source of the formulas on this page
\[ 2x - 5 = -1\ \Rightarrow\ x = 2 \]
\[ 2x - 5 = -1 \]
\[ 2x - 5 + 5 = -1 + 5 \ \Rightarrow\ 2x = 4 \]
\[ \frac{2x}{2} = \frac{4}{2} \ \Rightarrow\ x = 2 \]
\[ 2\cdot2 - 5 = 4 - 5 = -1 \checkmark \]

Trying values of x in 2x āˆ’ 5 = āˆ’1

x2x āˆ’ 5Equals -1?
0-5no
1-3no
2-1yes
31no
43no

Questions

What is x in 2x āˆ’ 5 = āˆ’1?

The solution of 2x āˆ’ 5 = āˆ’1 is x = 2.

How do you solve 2x āˆ’ 5 = āˆ’1?

Add 5 to both sides to get 2x = 4, then divide both sides by 2 to get x = 2.

How do I check the answer?

Replace x by 2: 2(2) āˆ’ 5 = -1, which is -1.

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