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Solve 2x āˆ’ 5 = 15

The solution of 2x āˆ’ 5 = 15 is x = 10.

The lines y = 2x āˆ’ 5 and y = 15 meet at x = 1046810121416510152025x = 10y = 2x āˆ’ 5y = 15
The lines y = 2x āˆ’ 5 and y = 15 meet at x = 10. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    2xāˆ’5=152x - 5 = 15
  2. 2

    Add 5 to both sides:

    2xāˆ’5+5=15+5 ⇒ 2x=202x - 5 + 5 = 15 + 5 \ \Rightarrow\ 2x = 20
  3. 3

    Divide both sides by 2:

    2x2=202 ⇒ x=10\frac{2x}{2} = \frac{20}{2} \ \Rightarrow\ x = 10
  4. 4

    Check: put x = 10 back into the equation.

    2ā‹…10āˆ’5=20āˆ’5=15āœ“2\cdot10 - 5 = 20 - 5 = 15 \checkmark
LaTeX source of the formulas on this page
\[ 2x - 5 = 15\ \Rightarrow\ x = 10 \]
\[ 2x - 5 = 15 \]
\[ 2x - 5 + 5 = 15 + 5 \ \Rightarrow\ 2x = 20 \]
\[ \frac{2x}{2} = \frac{20}{2} \ \Rightarrow\ x = 10 \]
\[ 2\cdot10 - 5 = 20 - 5 = 15 \checkmark \]

Trying values of x in 2x āˆ’ 5 = 15

x2x āˆ’ 5Equals 15?
811no
913no
1015yes
1117no
1219no

Questions

What is x in 2x āˆ’ 5 = 15?

The solution of 2x āˆ’ 5 = 15 is x = 10.

How do you solve 2x āˆ’ 5 = 15?

Add 5 to both sides to get 2x = 20, then divide both sides by 2 to get x = 10.

How do I check the answer?

Replace x by 10: 2(10) āˆ’ 5 = 15, which is 15.

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