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Solve 2x āˆ’ 2 = āˆ’22

The solution of 2x āˆ’ 2 = āˆ’22 is x = -10.

The lines y = 2x āˆ’ 2 and y = -22 meet at x = -10-16-14-12-10-8-6-4-35-30-25-20-15-10x = -10y = 2x āˆ’ 2y = -22
The lines y = 2x āˆ’ 2 and y = -22 meet at x = -10. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    2xāˆ’2=āˆ’222x - 2 = -22
  2. 2

    Add 2 to both sides:

    2xāˆ’2+2=āˆ’22+2 ⇒ 2x=āˆ’202x - 2 + 2 = -22 + 2 \ \Rightarrow\ 2x = -20
  3. 3

    Divide both sides by 2:

    2x2=āˆ’202 ⇒ x=āˆ’10\frac{2x}{2} = \frac{-20}{2} \ \Rightarrow\ x = -10
  4. 4

    Check: put x = -10 back into the equation.

    2ā‹…(āˆ’10)āˆ’2=āˆ’20āˆ’2=āˆ’22āœ“2\cdot(-10) - 2 = -20 - 2 = -22 \checkmark
LaTeX source of the formulas on this page
\[ 2x - 2 = -22\ \Rightarrow\ x = -10 \]
\[ 2x - 2 = -22 \]
\[ 2x - 2 + 2 = -22 + 2 \ \Rightarrow\ 2x = -20 \]
\[ \frac{2x}{2} = \frac{-20}{2} \ \Rightarrow\ x = -10 \]
\[ 2\cdot(-10) - 2 = -20 - 2 = -22 \checkmark \]

Trying values of x in 2x āˆ’ 2 = āˆ’22

x2x āˆ’ 2Equals -22?
-12-26no
-11-24no
-10-22yes
-9-20no
-8-18no

Questions

What is x in 2x āˆ’ 2 = āˆ’22?

The solution of 2x āˆ’ 2 = āˆ’22 is x = -10.

How do you solve 2x āˆ’ 2 = āˆ’22?

Add 2 to both sides to get 2x = -20, then divide both sides by 2 to get x = -10.

How do I check the answer?

Replace x by -10: 2(-10) āˆ’ 2 = -22, which is -22.

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    Solve 2x āˆ’ 2 = āˆ’22: x = -10 (steps and check) | WordGPT