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Solve 2x āˆ’ 15 = āˆ’5

The solution of 2x āˆ’ 15 = āˆ’5 is x = 5.

The lines y = 2x āˆ’ 15 and y = -5 meet at x = 5246810-15-10-55x = 5y = 2x āˆ’ 15y = -5
The lines y = 2x āˆ’ 15 and y = -5 meet at x = 5. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    2xāˆ’15=āˆ’52x - 15 = -5
  2. 2

    Add 15 to both sides:

    2xāˆ’15+15=āˆ’5+15 ⇒ 2x=102x - 15 + 15 = -5 + 15 \ \Rightarrow\ 2x = 10
  3. 3

    Divide both sides by 2:

    2x2=102 ⇒ x=5\frac{2x}{2} = \frac{10}{2} \ \Rightarrow\ x = 5
  4. 4

    Check: put x = 5 back into the equation.

    2ā‹…5āˆ’15=10āˆ’15=āˆ’5āœ“2\cdot5 - 15 = 10 - 15 = -5 \checkmark
LaTeX source of the formulas on this page
\[ 2x - 15 = -5\ \Rightarrow\ x = 5 \]
\[ 2x - 15 = -5 \]
\[ 2x - 15 + 15 = -5 + 15 \ \Rightarrow\ 2x = 10 \]
\[ \frac{2x}{2} = \frac{10}{2} \ \Rightarrow\ x = 5 \]
\[ 2\cdot5 - 15 = 10 - 15 = -5 \checkmark \]

Trying values of x in 2x āˆ’ 15 = āˆ’5

x2x āˆ’ 15Equals -5?
3-9no
4-7no
5-5yes
6-3no
7-1no

Questions

What is x in 2x āˆ’ 15 = āˆ’5?

The solution of 2x āˆ’ 15 = āˆ’5 is x = 5.

How do you solve 2x āˆ’ 15 = āˆ’5?

Add 15 to both sides to get 2x = 10, then divide both sides by 2 to get x = 5.

How do I check the answer?

Replace x by 5: 2(5) āˆ’ 15 = -5, which is -5.

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    Solve 2x āˆ’ 15 = āˆ’5: x = 5 (steps and check) | WordGPT