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Solve 2x āˆ’ 15 = āˆ’29

The solution of 2x āˆ’ 15 = āˆ’29 is x = -7.

The lines y = 2x āˆ’ 15 and y = -29 meet at x = -7-12-10-8-6-4-2-40-35-30-25-20-15x = -7y = 2x āˆ’ 15y = -29
The lines y = 2x āˆ’ 15 and y = -29 meet at x = -7. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    2xāˆ’15=āˆ’292x - 15 = -29
  2. 2

    Add 15 to both sides:

    2xāˆ’15+15=āˆ’29+15 ⇒ 2x=āˆ’142x - 15 + 15 = -29 + 15 \ \Rightarrow\ 2x = -14
  3. 3

    Divide both sides by 2:

    2x2=āˆ’142 ⇒ x=āˆ’7\frac{2x}{2} = \frac{-14}{2} \ \Rightarrow\ x = -7
  4. 4

    Check: put x = -7 back into the equation.

    2ā‹…(āˆ’7)āˆ’15=āˆ’14āˆ’15=āˆ’29āœ“2\cdot(-7) - 15 = -14 - 15 = -29 \checkmark
LaTeX source of the formulas on this page
\[ 2x - 15 = -29\ \Rightarrow\ x = -7 \]
\[ 2x - 15 = -29 \]
\[ 2x - 15 + 15 = -29 + 15 \ \Rightarrow\ 2x = -14 \]
\[ \frac{2x}{2} = \frac{-14}{2} \ \Rightarrow\ x = -7 \]
\[ 2\cdot(-7) - 15 = -14 - 15 = -29 \checkmark \]

Trying values of x in 2x āˆ’ 15 = āˆ’29

x2x āˆ’ 15Equals -29?
-9-33no
-8-31no
-7-29yes
-6-27no
-5-25no

Questions

What is x in 2x āˆ’ 15 = āˆ’29?

The solution of 2x āˆ’ 15 = āˆ’29 is x = -7.

How do you solve 2x āˆ’ 15 = āˆ’29?

Add 15 to both sides to get 2x = -14, then divide both sides by 2 to get x = -7.

How do I check the answer?

Replace x by -7: 2(-7) āˆ’ 15 = -29, which is -29.

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    Solve 2x āˆ’ 15 = āˆ’29: x = -7 (steps and check) | WordGPT