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Solve 2x āˆ’ 12 = 28

The solution of 2x āˆ’ 12 = 28 is x = 20.

The lines y = 2x āˆ’ 12 and y = 28 meet at x = 2014161820222426152025303540x = 20y = 2x āˆ’ 12y = 28
The lines y = 2x āˆ’ 12 and y = 28 meet at x = 20. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    2xāˆ’12=282x - 12 = 28
  2. 2

    Add 12 to both sides:

    2xāˆ’12+12=28+12 ⇒ 2x=402x - 12 + 12 = 28 + 12 \ \Rightarrow\ 2x = 40
  3. 3

    Divide both sides by 2:

    2x2=402 ⇒ x=20\frac{2x}{2} = \frac{40}{2} \ \Rightarrow\ x = 20
  4. 4

    Check: put x = 20 back into the equation.

    2ā‹…20āˆ’12=40āˆ’12=28āœ“2\cdot20 - 12 = 40 - 12 = 28 \checkmark
LaTeX source of the formulas on this page
\[ 2x - 12 = 28\ \Rightarrow\ x = 20 \]
\[ 2x - 12 = 28 \]
\[ 2x - 12 + 12 = 28 + 12 \ \Rightarrow\ 2x = 40 \]
\[ \frac{2x}{2} = \frac{40}{2} \ \Rightarrow\ x = 20 \]
\[ 2\cdot20 - 12 = 40 - 12 = 28 \checkmark \]

Trying values of x in 2x āˆ’ 12 = 28

x2x āˆ’ 12Equals 28?
1824no
1926no
2028yes
2130no
2232no

Questions

What is x in 2x āˆ’ 12 = 28?

The solution of 2x āˆ’ 12 = 28 is x = 20.

How do you solve 2x āˆ’ 12 = 28?

Add 12 to both sides to get 2x = 40, then divide both sides by 2 to get x = 20.

How do I check the answer?

Replace x by 20: 2(20) āˆ’ 12 = 28, which is 28.

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