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Solve 2x āˆ’ 12 = 20

The solution of 2x āˆ’ 12 = 20 is x = 16.

The lines y = 2x āˆ’ 12 and y = 20 meet at x = 16101214161820221015202530x = 16y = 2x āˆ’ 12y = 20
The lines y = 2x āˆ’ 12 and y = 20 meet at x = 16. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    2xāˆ’12=202x - 12 = 20
  2. 2

    Add 12 to both sides:

    2xāˆ’12+12=20+12 ⇒ 2x=322x - 12 + 12 = 20 + 12 \ \Rightarrow\ 2x = 32
  3. 3

    Divide both sides by 2:

    2x2=322 ⇒ x=16\frac{2x}{2} = \frac{32}{2} \ \Rightarrow\ x = 16
  4. 4

    Check: put x = 16 back into the equation.

    2ā‹…16āˆ’12=32āˆ’12=20āœ“2\cdot16 - 12 = 32 - 12 = 20 \checkmark
LaTeX source of the formulas on this page
\[ 2x - 12 = 20\ \Rightarrow\ x = 16 \]
\[ 2x - 12 = 20 \]
\[ 2x - 12 + 12 = 20 + 12 \ \Rightarrow\ 2x = 32 \]
\[ \frac{2x}{2} = \frac{32}{2} \ \Rightarrow\ x = 16 \]
\[ 2\cdot16 - 12 = 32 - 12 = 20 \checkmark \]

Trying values of x in 2x āˆ’ 12 = 20

x2x āˆ’ 12Equals 20?
1416no
1518no
1620yes
1722no
1824no

Questions

What is x in 2x āˆ’ 12 = 20?

The solution of 2x āˆ’ 12 = 20 is x = 16.

How do you solve 2x āˆ’ 12 = 20?

Add 12 to both sides to get 2x = 32, then divide both sides by 2 to get x = 16.

How do I check the answer?

Replace x by 16: 2(16) āˆ’ 12 = 20, which is 20.

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