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Solve 2x āˆ’ 12 = 0

The solution of 2x āˆ’ 12 = 0 is x = 6.

The lines y = 2x āˆ’ 12 and y = 0 meet at x = 624681012-10-5510x = 6y = 2x āˆ’ 12y = 0
The lines y = 2x āˆ’ 12 and y = 0 meet at x = 6. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    2xāˆ’12=02x - 12 = 0
  2. 2

    Add 12 to both sides:

    2xāˆ’12+12=0+12 ⇒ 2x=122x - 12 + 12 = 0 + 12 \ \Rightarrow\ 2x = 12
  3. 3

    Divide both sides by 2:

    2x2=122 ⇒ x=6\frac{2x}{2} = \frac{12}{2} \ \Rightarrow\ x = 6
  4. 4

    Check: put x = 6 back into the equation.

    2ā‹…6āˆ’12=12āˆ’12=0āœ“2\cdot6 - 12 = 12 - 12 = 0 \checkmark
LaTeX source of the formulas on this page
\[ 2x - 12 = 0\ \Rightarrow\ x = 6 \]
\[ 2x - 12 = 0 \]
\[ 2x - 12 + 12 = 0 + 12 \ \Rightarrow\ 2x = 12 \]
\[ \frac{2x}{2} = \frac{12}{2} \ \Rightarrow\ x = 6 \]
\[ 2\cdot6 - 12 = 12 - 12 = 0 \checkmark \]

Trying values of x in 2x āˆ’ 12 = 0

x2x āˆ’ 12Equals 0?
4-4no
5-2no
60yes
72no
84no

Questions

What is x in 2x āˆ’ 12 = 0?

The solution of 2x āˆ’ 12 = 0 is x = 6.

How do you solve 2x āˆ’ 12 = 0?

Add 12 to both sides to get 2x = 12, then divide both sides by 2 to get x = 6.

How do I check the answer?

Replace x by 6: 2(6) āˆ’ 12 = 0, which is 0.

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