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Solve 2x āˆ’ 11 = 29

The solution of 2x āˆ’ 11 = 29 is x = 20.

The lines y = 2x āˆ’ 11 and y = 29 meet at x = 2014161820222426152025303540x = 20y = 2x āˆ’ 11y = 29
The lines y = 2x āˆ’ 11 and y = 29 meet at x = 20. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    2xāˆ’11=292x - 11 = 29
  2. 2

    Add 11 to both sides:

    2xāˆ’11+11=29+11 ⇒ 2x=402x - 11 + 11 = 29 + 11 \ \Rightarrow\ 2x = 40
  3. 3

    Divide both sides by 2:

    2x2=402 ⇒ x=20\frac{2x}{2} = \frac{40}{2} \ \Rightarrow\ x = 20
  4. 4

    Check: put x = 20 back into the equation.

    2ā‹…20āˆ’11=40āˆ’11=29āœ“2\cdot20 - 11 = 40 - 11 = 29 \checkmark
LaTeX source of the formulas on this page
\[ 2x - 11 = 29\ \Rightarrow\ x = 20 \]
\[ 2x - 11 = 29 \]
\[ 2x - 11 + 11 = 29 + 11 \ \Rightarrow\ 2x = 40 \]
\[ \frac{2x}{2} = \frac{40}{2} \ \Rightarrow\ x = 20 \]
\[ 2\cdot20 - 11 = 40 - 11 = 29 \checkmark \]

Trying values of x in 2x āˆ’ 11 = 29

x2x āˆ’ 11Equals 29?
1825no
1927no
2029yes
2131no
2233no

Questions

What is x in 2x āˆ’ 11 = 29?

The solution of 2x āˆ’ 11 = 29 is x = 20.

How do you solve 2x āˆ’ 11 = 29?

Add 11 to both sides to get 2x = 40, then divide both sides by 2 to get x = 20.

How do I check the answer?

Replace x by 20: 2(20) āˆ’ 11 = 29, which is 29.

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