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Solve 2x āˆ’ 10 = āˆ’20

The solution of 2x āˆ’ 10 = āˆ’20 is x = -5.

The lines y = 2x āˆ’ 10 and y = -20 meet at x = -5-10-8-6-4-2-30-25-20-15-10x = -5y = 2x āˆ’ 10y = -20
The lines y = 2x āˆ’ 10 and y = -20 meet at x = -5. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    2xāˆ’10=āˆ’202x - 10 = -20
  2. 2

    Add 10 to both sides:

    2xāˆ’10+10=āˆ’20+10 ⇒ 2x=āˆ’102x - 10 + 10 = -20 + 10 \ \Rightarrow\ 2x = -10
  3. 3

    Divide both sides by 2:

    2x2=āˆ’102 ⇒ x=āˆ’5\frac{2x}{2} = \frac{-10}{2} \ \Rightarrow\ x = -5
  4. 4

    Check: put x = -5 back into the equation.

    2ā‹…(āˆ’5)āˆ’10=āˆ’10āˆ’10=āˆ’20āœ“2\cdot(-5) - 10 = -10 - 10 = -20 \checkmark
LaTeX source of the formulas on this page
\[ 2x - 10 = -20\ \Rightarrow\ x = -5 \]
\[ 2x - 10 = -20 \]
\[ 2x - 10 + 10 = -20 + 10 \ \Rightarrow\ 2x = -10 \]
\[ \frac{2x}{2} = \frac{-10}{2} \ \Rightarrow\ x = -5 \]
\[ 2\cdot(-5) - 10 = -10 - 10 = -20 \checkmark \]

Trying values of x in 2x āˆ’ 10 = āˆ’20

x2x āˆ’ 10Equals -20?
-7-24no
-6-22no
-5-20yes
-4-18no
-3-16no

Questions

What is x in 2x āˆ’ 10 = āˆ’20?

The solution of 2x āˆ’ 10 = āˆ’20 is x = -5.

How do you solve 2x āˆ’ 10 = āˆ’20?

Add 10 to both sides to get 2x = -10, then divide both sides by 2 to get x = -5.

How do I check the answer?

Replace x by -5: 2(-5) āˆ’ 10 = -20, which is -20.

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    Solve 2x āˆ’ 10 = āˆ’20: x = -5 (steps and check) | WordGPT