Solve 12x + 8 = ā64
The solution of 12x + 8 = ā64 is x = -6.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 8 from both sides:
- 3
Divide both sides by 12:
- 4
Check: put x = -6 back into the equation.
LaTeX source of the formulas on this page
\[ 12x + 8 = -64\ \Rightarrow\ x = -6 \]
\[ 12x + 8 = -64 \]
\[ 12x + 8 - 8 = -64 - 8 \ \Rightarrow\ 12x = -72 \]
\[ \frac{12x}{12} = \frac{-72}{12} \ \Rightarrow\ x = -6 \]
\[ 12\cdot(-6) + 8 = -72 + 8 = -64 \checkmark \]Trying values of x in 12x + 8 = ā64
| x | 12x + 8 | Equals -64? |
|---|---|---|
| -8 | -88 | no |
| -7 | -76 | no |
| -6 | -64 | yes |
| -5 | -52 | no |
| -4 | -40 | no |
Questions
What is x in 12x + 8 = ā64?
The solution of 12x + 8 = ā64 is x = -6.
How do you solve 12x + 8 = ā64?
Subtract 8 from both sides to get 12x = -72, then divide both sides by 12 to get x = -6.
How do I check the answer?
Replace x by -6: 12(-6) + 8 = -64, which is -64.