Solve 12x + 8 = 20
The solution of 12x + 8 = 20 is x = 1.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 8 from both sides:
- 3
Divide both sides by 12:
- 4
Check: put x = 1 back into the equation.
LaTeX source of the formulas on this page
\[ 12x + 8 = 20\ \Rightarrow\ x = 1 \]
\[ 12x + 8 = 20 \]
\[ 12x + 8 - 8 = 20 - 8 \ \Rightarrow\ 12x = 12 \]
\[ \frac{12x}{12} = \frac{12}{12} \ \Rightarrow\ x = 1 \]
\[ 12\cdot1 + 8 = 12 + 8 = 20 \checkmark \]Trying values of x in 12x + 8 = 20
| x | 12x + 8 | Equals 20? |
|---|---|---|
| -1 | -4 | no |
| 0 | 8 | no |
| 1 | 20 | yes |
| 2 | 32 | no |
| 3 | 44 | no |
Questions
What is x in 12x + 8 = 20?
The solution of 12x + 8 = 20 is x = 1.
How do you solve 12x + 8 = 20?
Subtract 8 from both sides to get 12x = 12, then divide both sides by 12 to get x = 1.
How do I check the answer?
Replace x by 1: 12(1) + 8 = 20, which is 20.