Solve 12x + 7 = 223
The solution of 12x + 7 = 223 is x = 18.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 7 from both sides:
- 3
Divide both sides by 12:
- 4
Check: put x = 18 back into the equation.
LaTeX source of the formulas on this page
\[ 12x + 7 = 223\ \Rightarrow\ x = 18 \]
\[ 12x + 7 = 223 \]
\[ 12x + 7 - 7 = 223 - 7 \ \Rightarrow\ 12x = 216 \]
\[ \frac{12x}{12} = \frac{216}{12} \ \Rightarrow\ x = 18 \]
\[ 12\cdot18 + 7 = 216 + 7 = 223 \checkmark \]Trying values of x in 12x + 7 = 223
| x | 12x + 7 | Equals 223? |
|---|---|---|
| 16 | 199 | no |
| 17 | 211 | no |
| 18 | 223 | yes |
| 19 | 235 | no |
| 20 | 247 | no |
Questions
What is x in 12x + 7 = 223?
The solution of 12x + 7 = 223 is x = 18.
How do you solve 12x + 7 = 223?
Subtract 7 from both sides to get 12x = 216, then divide both sides by 12 to get x = 18.
How do I check the answer?
Replace x by 18: 12(18) + 7 = 223, which is 223.