Solve 12x + 6 = ā90
The solution of 12x + 6 = ā90 is x = -8.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 6 from both sides:
- 3
Divide both sides by 12:
- 4
Check: put x = -8 back into the equation.
LaTeX source of the formulas on this page
\[ 12x + 6 = -90\ \Rightarrow\ x = -8 \]
\[ 12x + 6 = -90 \]
\[ 12x + 6 - 6 = -90 - 6 \ \Rightarrow\ 12x = -96 \]
\[ \frac{12x}{12} = \frac{-96}{12} \ \Rightarrow\ x = -8 \]
\[ 12\cdot(-8) + 6 = -96 + 6 = -90 \checkmark \]Trying values of x in 12x + 6 = ā90
| x | 12x + 6 | Equals -90? |
|---|---|---|
| -10 | -114 | no |
| -9 | -102 | no |
| -8 | -90 | yes |
| -7 | -78 | no |
| -6 | -66 | no |
Questions
What is x in 12x + 6 = ā90?
The solution of 12x + 6 = ā90 is x = -8.
How do you solve 12x + 6 = ā90?
Subtract 6 from both sides to get 12x = -96, then divide both sides by 12 to get x = -8.
How do I check the answer?
Replace x by -8: 12(-8) + 6 = -90, which is -90.