Solve 12x + 6 = ā66
The solution of 12x + 6 = ā66 is x = -6.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 6 from both sides:
- 3
Divide both sides by 12:
- 4
Check: put x = -6 back into the equation.
LaTeX source of the formulas on this page
\[ 12x + 6 = -66\ \Rightarrow\ x = -6 \]
\[ 12x + 6 = -66 \]
\[ 12x + 6 - 6 = -66 - 6 \ \Rightarrow\ 12x = -72 \]
\[ \frac{12x}{12} = \frac{-72}{12} \ \Rightarrow\ x = -6 \]
\[ 12\cdot(-6) + 6 = -72 + 6 = -66 \checkmark \]Trying values of x in 12x + 6 = ā66
| x | 12x + 6 | Equals -66? |
|---|---|---|
| -8 | -90 | no |
| -7 | -78 | no |
| -6 | -66 | yes |
| -5 | -54 | no |
| -4 | -42 | no |
Questions
What is x in 12x + 6 = ā66?
The solution of 12x + 6 = ā66 is x = -6.
How do you solve 12x + 6 = ā66?
Subtract 6 from both sides to get 12x = -72, then divide both sides by 12 to get x = -6.
How do I check the answer?
Replace x by -6: 12(-6) + 6 = -66, which is -66.