Solve 12x + 5 = ā115
The solution of 12x + 5 = ā115 is x = -10.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 5 from both sides:
- 3
Divide both sides by 12:
- 4
Check: put x = -10 back into the equation.
LaTeX source of the formulas on this page
\[ 12x + 5 = -115\ \Rightarrow\ x = -10 \]
\[ 12x + 5 = -115 \]
\[ 12x + 5 - 5 = -115 - 5 \ \Rightarrow\ 12x = -120 \]
\[ \frac{12x}{12} = \frac{-120}{12} \ \Rightarrow\ x = -10 \]
\[ 12\cdot(-10) + 5 = -120 + 5 = -115 \checkmark \]Trying values of x in 12x + 5 = ā115
| x | 12x + 5 | Equals -115? |
|---|---|---|
| -12 | -139 | no |
| -11 | -127 | no |
| -10 | -115 | yes |
| -9 | -103 | no |
| -8 | -91 | no |
Questions
What is x in 12x + 5 = ā115?
The solution of 12x + 5 = ā115 is x = -10.
How do you solve 12x + 5 = ā115?
Subtract 5 from both sides to get 12x = -120, then divide both sides by 12 to get x = -10.
How do I check the answer?
Replace x by -10: 12(-10) + 5 = -115, which is -115.