Solve 12x + 5 = 221
The solution of 12x + 5 = 221 is x = 18.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 5 from both sides:
- 3
Divide both sides by 12:
- 4
Check: put x = 18 back into the equation.
LaTeX source of the formulas on this page
\[ 12x + 5 = 221\ \Rightarrow\ x = 18 \]
\[ 12x + 5 = 221 \]
\[ 12x + 5 - 5 = 221 - 5 \ \Rightarrow\ 12x = 216 \]
\[ \frac{12x}{12} = \frac{216}{12} \ \Rightarrow\ x = 18 \]
\[ 12\cdot18 + 5 = 216 + 5 = 221 \checkmark \]Trying values of x in 12x + 5 = 221
| x | 12x + 5 | Equals 221? |
|---|---|---|
| 16 | 197 | no |
| 17 | 209 | no |
| 18 | 221 | yes |
| 19 | 233 | no |
| 20 | 245 | no |
Questions
What is x in 12x + 5 = 221?
The solution of 12x + 5 = 221 is x = 18.
How do you solve 12x + 5 = 221?
Subtract 5 from both sides to get 12x = 216, then divide both sides by 12 to get x = 18.
How do I check the answer?
Replace x by 18: 12(18) + 5 = 221, which is 221.