Solve 12x + 4 = ā92
The solution of 12x + 4 = ā92 is x = -8.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 4 from both sides:
- 3
Divide both sides by 12:
- 4
Check: put x = -8 back into the equation.
LaTeX source of the formulas on this page
\[ 12x + 4 = -92\ \Rightarrow\ x = -8 \]
\[ 12x + 4 = -92 \]
\[ 12x + 4 - 4 = -92 - 4 \ \Rightarrow\ 12x = -96 \]
\[ \frac{12x}{12} = \frac{-96}{12} \ \Rightarrow\ x = -8 \]
\[ 12\cdot(-8) + 4 = -96 + 4 = -92 \checkmark \]Trying values of x in 12x + 4 = ā92
| x | 12x + 4 | Equals -92? |
|---|---|---|
| -10 | -116 | no |
| -9 | -104 | no |
| -8 | -92 | yes |
| -7 | -80 | no |
| -6 | -68 | no |
Questions
What is x in 12x + 4 = ā92?
The solution of 12x + 4 = ā92 is x = -8.
How do you solve 12x + 4 = ā92?
Subtract 4 from both sides to get 12x = -96, then divide both sides by 12 to get x = -8.
How do I check the answer?
Replace x by -8: 12(-8) + 4 = -92, which is -92.