Solve 12x + 4 = 4
The solution of 12x + 4 = 4 is x = 0.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 4 from both sides:
- 3
Divide both sides by 12:
- 4
Check: put x = 0 back into the equation.
LaTeX source of the formulas on this page
\[ 12x + 4 = 4\ \Rightarrow\ x = 0 \]
\[ 12x + 4 = 4 \]
\[ 12x + 4 - 4 = 4 - 4 \ \Rightarrow\ 12x = 0 \]
\[ \frac{12x}{12} = \frac{0}{12} \ \Rightarrow\ x = 0 \]
\[ 12\cdot0 + 4 = 0 + 4 = 4 \checkmark \]Trying values of x in 12x + 4 = 4
| x | 12x + 4 | Equals 4? |
|---|---|---|
| -2 | -20 | no |
| -1 | -8 | no |
| 0 | 4 | yes |
| 1 | 16 | no |
| 2 | 28 | no |
Questions
What is x in 12x + 4 = 4?
The solution of 12x + 4 = 4 is x = 0.
How do you solve 12x + 4 = 4?
Subtract 4 from both sides to get 12x = 0, then divide both sides by 12 to get x = 0.
How do I check the answer?
Replace x by 0: 12(0) + 4 = 4, which is 4.