Solve 12x + 2 = ā118
The solution of 12x + 2 = ā118 is x = -10.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 2 from both sides:
- 3
Divide both sides by 12:
- 4
Check: put x = -10 back into the equation.
LaTeX source of the formulas on this page
\[ 12x + 2 = -118\ \Rightarrow\ x = -10 \]
\[ 12x + 2 = -118 \]
\[ 12x + 2 - 2 = -118 - 2 \ \Rightarrow\ 12x = -120 \]
\[ \frac{12x}{12} = \frac{-120}{12} \ \Rightarrow\ x = -10 \]
\[ 12\cdot(-10) + 2 = -120 + 2 = -118 \checkmark \]Trying values of x in 12x + 2 = ā118
| x | 12x + 2 | Equals -118? |
|---|---|---|
| -12 | -142 | no |
| -11 | -130 | no |
| -10 | -118 | yes |
| -9 | -106 | no |
| -8 | -94 | no |
Questions
What is x in 12x + 2 = ā118?
The solution of 12x + 2 = ā118 is x = -10.
How do you solve 12x + 2 = ā118?
Subtract 2 from both sides to get 12x = -120, then divide both sides by 12 to get x = -10.
How do I check the answer?
Replace x by -10: 12(-10) + 2 = -118, which is -118.