Solve 12x + 2 = 38
The solution of 12x + 2 = 38 is x = 3.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 2 from both sides:
- 3
Divide both sides by 12:
- 4
Check: put x = 3 back into the equation.
LaTeX source of the formulas on this page
\[ 12x + 2 = 38\ \Rightarrow\ x = 3 \]
\[ 12x + 2 = 38 \]
\[ 12x + 2 - 2 = 38 - 2 \ \Rightarrow\ 12x = 36 \]
\[ \frac{12x}{12} = \frac{36}{12} \ \Rightarrow\ x = 3 \]
\[ 12\cdot3 + 2 = 36 + 2 = 38 \checkmark \]Trying values of x in 12x + 2 = 38
| x | 12x + 2 | Equals 38? |
|---|---|---|
| 1 | 14 | no |
| 2 | 26 | no |
| 3 | 38 | yes |
| 4 | 50 | no |
| 5 | 62 | no |
Questions
What is x in 12x + 2 = 38?
The solution of 12x + 2 = 38 is x = 3.
How do you solve 12x + 2 = 38?
Subtract 2 from both sides to get 12x = 36, then divide both sides by 12 to get x = 3.
How do I check the answer?
Replace x by 3: 12(3) + 2 = 38, which is 38.