Solve 12x + 15 = 63
The solution of 12x + 15 = 63 is x = 4.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 15 from both sides:
- 3
Divide both sides by 12:
- 4
Check: put x = 4 back into the equation.
LaTeX source of the formulas on this page
\[ 12x + 15 = 63\ \Rightarrow\ x = 4 \]
\[ 12x + 15 = 63 \]
\[ 12x + 15 - 15 = 63 - 15 \ \Rightarrow\ 12x = 48 \]
\[ \frac{12x}{12} = \frac{48}{12} \ \Rightarrow\ x = 4 \]
\[ 12\cdot4 + 15 = 48 + 15 = 63 \checkmark \]Trying values of x in 12x + 15 = 63
| x | 12x + 15 | Equals 63? |
|---|---|---|
| 2 | 39 | no |
| 3 | 51 | no |
| 4 | 63 | yes |
| 5 | 75 | no |
| 6 | 87 | no |
Questions
What is x in 12x + 15 = 63?
The solution of 12x + 15 = 63 is x = 4.
How do you solve 12x + 15 = 63?
Subtract 15 from both sides to get 12x = 48, then divide both sides by 12 to get x = 4.
How do I check the answer?
Replace x by 4: 12(4) + 15 = 63, which is 63.