Solve 12x + 15 = 147
The solution of 12x + 15 = 147 is x = 11.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 15 from both sides:
- 3
Divide both sides by 12:
- 4
Check: put x = 11 back into the equation.
LaTeX source of the formulas on this page
\[ 12x + 15 = 147\ \Rightarrow\ x = 11 \]
\[ 12x + 15 = 147 \]
\[ 12x + 15 - 15 = 147 - 15 \ \Rightarrow\ 12x = 132 \]
\[ \frac{12x}{12} = \frac{132}{12} \ \Rightarrow\ x = 11 \]
\[ 12\cdot11 + 15 = 132 + 15 = 147 \checkmark \]Trying values of x in 12x + 15 = 147
| x | 12x + 15 | Equals 147? |
|---|---|---|
| 9 | 123 | no |
| 10 | 135 | no |
| 11 | 147 | yes |
| 12 | 159 | no |
| 13 | 171 | no |
Questions
What is x in 12x + 15 = 147?
The solution of 12x + 15 = 147 is x = 11.
How do you solve 12x + 15 = 147?
Subtract 15 from both sides to get 12x = 132, then divide both sides by 12 to get x = 11.
How do I check the answer?
Replace x by 11: 12(11) + 15 = 147, which is 147.