Solve 12x + 12 = ā96
The solution of 12x + 12 = ā96 is x = -9.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 12 from both sides:
- 3
Divide both sides by 12:
- 4
Check: put x = -9 back into the equation.
LaTeX source of the formulas on this page
\[ 12x + 12 = -96\ \Rightarrow\ x = -9 \]
\[ 12x + 12 = -96 \]
\[ 12x + 12 - 12 = -96 - 12 \ \Rightarrow\ 12x = -108 \]
\[ \frac{12x}{12} = \frac{-108}{12} \ \Rightarrow\ x = -9 \]
\[ 12\cdot(-9) + 12 = -108 + 12 = -96 \checkmark \]Trying values of x in 12x + 12 = ā96
| x | 12x + 12 | Equals -96? |
|---|---|---|
| -11 | -120 | no |
| -10 | -108 | no |
| -9 | -96 | yes |
| -8 | -84 | no |
| -7 | -72 | no |
Questions
What is x in 12x + 12 = ā96?
The solution of 12x + 12 = ā96 is x = -9.
How do you solve 12x + 12 = ā96?
Subtract 12 from both sides to get 12x = -108, then divide both sides by 12 to get x = -9.
How do I check the answer?
Replace x by -9: 12(-9) + 12 = -96, which is -96.