Solve 12x + 12 = 0
The solution of 12x + 12 = 0 is x = -1.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 12 from both sides:
- 3
Divide both sides by 12:
- 4
Check: put x = -1 back into the equation.
LaTeX source of the formulas on this page
\[ 12x + 12 = 0\ \Rightarrow\ x = -1 \]
\[ 12x + 12 = 0 \]
\[ 12x + 12 - 12 = 0 - 12 \ \Rightarrow\ 12x = -12 \]
\[ \frac{12x}{12} = \frac{-12}{12} \ \Rightarrow\ x = -1 \]
\[ 12\cdot(-1) + 12 = -12 + 12 = 0 \checkmark \]Trying values of x in 12x + 12 = 0
| x | 12x + 12 | Equals 0? |
|---|---|---|
| -3 | -24 | no |
| -2 | -12 | no |
| -1 | 0 | yes |
| 0 | 12 | no |
| 1 | 24 | no |
Questions
What is x in 12x + 12 = 0?
The solution of 12x + 12 = 0 is x = -1.
How do you solve 12x + 12 = 0?
Subtract 12 from both sides to get 12x = -12, then divide both sides by 12 to get x = -1.
How do I check the answer?
Replace x by -1: 12(-1) + 12 = 0, which is 0.