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Solve 12x + 10 = āˆ’38

The solution of 12x + 10 = āˆ’38 is x = -4.

The lines y = 12x + 10 and y = -38 meet at x = -4-10-8-6-4-22-120-100-80-60-40-202040x = -4y = 12x + 10y = -38
The lines y = 12x + 10 and y = -38 meet at x = -4. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    12x+10=āˆ’3812x + 10 = -38
  2. 2

    Subtract 10 from both sides:

    12x+10āˆ’10=āˆ’38āˆ’10 ⇒ 12x=āˆ’4812x + 10 - 10 = -38 - 10 \ \Rightarrow\ 12x = -48
  3. 3

    Divide both sides by 12:

    12x12=āˆ’4812 ⇒ x=āˆ’4\frac{12x}{12} = \frac{-48}{12} \ \Rightarrow\ x = -4
  4. 4

    Check: put x = -4 back into the equation.

    12ā‹…(āˆ’4)+10=āˆ’48+10=āˆ’38āœ“12\cdot(-4) + 10 = -48 + 10 = -38 \checkmark
LaTeX source of the formulas on this page
\[ 12x + 10 = -38\ \Rightarrow\ x = -4 \]
\[ 12x + 10 = -38 \]
\[ 12x + 10 - 10 = -38 - 10 \ \Rightarrow\ 12x = -48 \]
\[ \frac{12x}{12} = \frac{-48}{12} \ \Rightarrow\ x = -4 \]
\[ 12\cdot(-4) + 10 = -48 + 10 = -38 \checkmark \]

Trying values of x in 12x + 10 = āˆ’38

x12x + 10Equals -38?
-6-62no
-5-50no
-4-38yes
-3-26no
-2-14no

Questions

What is x in 12x + 10 = āˆ’38?

The solution of 12x + 10 = āˆ’38 is x = -4.

How do you solve 12x + 10 = āˆ’38?

Subtract 10 from both sides to get 12x = -48, then divide both sides by 12 to get x = -4.

How do I check the answer?

Replace x by -4: 12(-4) + 10 = -38, which is -38.

Similar equations

    Solve 12x + 10 = āˆ’38: x = -4 (steps and check) | WordGPT