Solve 12x + 10 = 202
The solution of 12x + 10 = 202 is x = 16.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 10 from both sides:
- 3
Divide both sides by 12:
- 4
Check: put x = 16 back into the equation.
LaTeX source of the formulas on this page
\[ 12x + 10 = 202\ \Rightarrow\ x = 16 \]
\[ 12x + 10 = 202 \]
\[ 12x + 10 - 10 = 202 - 10 \ \Rightarrow\ 12x = 192 \]
\[ \frac{12x}{12} = \frac{192}{12} \ \Rightarrow\ x = 16 \]
\[ 12\cdot16 + 10 = 192 + 10 = 202 \checkmark \]Trying values of x in 12x + 10 = 202
| x | 12x + 10 | Equals 202? |
|---|---|---|
| 14 | 178 | no |
| 15 | 190 | no |
| 16 | 202 | yes |
| 17 | 214 | no |
| 18 | 226 | no |
Questions
What is x in 12x + 10 = 202?
The solution of 12x + 10 = 202 is x = 16.
How do you solve 12x + 10 = 202?
Subtract 10 from both sides to get 12x = 192, then divide both sides by 12 to get x = 16.
How do I check the answer?
Replace x by 16: 12(16) + 10 = 202, which is 202.