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Solve 12x + 1 = āˆ’23

The solution of 12x + 1 = āˆ’23 is x = -2.

The lines y = 12x + 1 and y = -23 meet at x = -2-8-6-4-224-100-80-60-40-20204060x = -2y = 12x + 1y = -23
The lines y = 12x + 1 and y = -23 meet at x = -2. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    12x+1=āˆ’2312x + 1 = -23
  2. 2

    Subtract 1 from both sides:

    12x+1āˆ’1=āˆ’23āˆ’1 ⇒ 12x=āˆ’2412x + 1 - 1 = -23 - 1 \ \Rightarrow\ 12x = -24
  3. 3

    Divide both sides by 12:

    12x12=āˆ’2412 ⇒ x=āˆ’2\frac{12x}{12} = \frac{-24}{12} \ \Rightarrow\ x = -2
  4. 4

    Check: put x = -2 back into the equation.

    12ā‹…(āˆ’2)+1=āˆ’24+1=āˆ’23āœ“12\cdot(-2) + 1 = -24 + 1 = -23 \checkmark
LaTeX source of the formulas on this page
\[ 12x + 1 = -23\ \Rightarrow\ x = -2 \]
\[ 12x + 1 = -23 \]
\[ 12x + 1 - 1 = -23 - 1 \ \Rightarrow\ 12x = -24 \]
\[ \frac{12x}{12} = \frac{-24}{12} \ \Rightarrow\ x = -2 \]
\[ 12\cdot(-2) + 1 = -24 + 1 = -23 \checkmark \]

Trying values of x in 12x + 1 = āˆ’23

x12x + 1Equals -23?
-4-47no
-3-35no
-2-23yes
-1-11no
01no

Questions

What is x in 12x + 1 = āˆ’23?

The solution of 12x + 1 = āˆ’23 is x = -2.

How do you solve 12x + 1 = āˆ’23?

Subtract 1 from both sides to get 12x = -24, then divide both sides by 12 to get x = -2.

How do I check the answer?

Replace x by -2: 12(-2) + 1 = -23, which is -23.

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    Solve 12x + 1 = āˆ’23: x = -2 (steps and check) | WordGPT