Solve 12x + 1 = 97
The solution of 12x + 1 = 97 is x = 8.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 1 from both sides:
- 3
Divide both sides by 12:
- 4
Check: put x = 8 back into the equation.
LaTeX source of the formulas on this page
\[ 12x + 1 = 97\ \Rightarrow\ x = 8 \]
\[ 12x + 1 = 97 \]
\[ 12x + 1 - 1 = 97 - 1 \ \Rightarrow\ 12x = 96 \]
\[ \frac{12x}{12} = \frac{96}{12} \ \Rightarrow\ x = 8 \]
\[ 12\cdot8 + 1 = 96 + 1 = 97 \checkmark \]Trying values of x in 12x + 1 = 97
| x | 12x + 1 | Equals 97? |
|---|---|---|
| 6 | 73 | no |
| 7 | 85 | no |
| 8 | 97 | yes |
| 9 | 109 | no |
| 10 | 121 | no |
Questions
What is x in 12x + 1 = 97?
The solution of 12x + 1 = 97 is x = 8.
How do you solve 12x + 1 = 97?
Subtract 1 from both sides to get 12x = 96, then divide both sides by 12 to get x = 8.
How do I check the answer?
Replace x by 8: 12(8) + 1 = 97, which is 97.